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Question: Answered & Verified by Expert
The size of isoelectronic species \(-\mathrm{F}^{-}\), Ne and \(\mathrm{Na}^{+}\)is affected by
(a) nuclear charge (Z)
(b) valence principal quantum number (n)
(c) electron-electron interaction in the outer orbitals
(d) none of the factors because their size is the same.
ChemistryClassification of Elements and Periodicity in Properties
Solution:
1689 Upvotes Verified Answer
The size of the isoelectronic ions depends upon the nuclear charge \((Z)\). As the nuclear charge increases the size decreases. For example, \(\mathrm{F}^{-}(+9)>\mathrm{Ne}(+10)>\mathrm{Na}^{+}(+11)\). Therefore, statement (a) is correct while all other statements are wrong.

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