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The slope of the line through the origin which makes an angle of $30^{\circ}$ with the positive direction of $\mathrm{Y}$-axis measured anticlockwise is
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The correct answer is:
$-\sqrt{3}$
Refer figure
Angle made by line $\mathrm{L}$ with positive direction of $\mathrm{X}$ axis is $\left(90^{\circ}+30^{\circ}\right)$ i.e. $120^{\circ}$.
$\therefore$ Slope of line $\mathrm{L}=\tan \left(120^{\circ}\right)=\tan \left(\pi-60^{\circ}\right)=-\tan 60^{\circ}=-\sqrt{3}$
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