Join the Most Relevant JEE Main 2025 Test Series & get 99+ percentile! Join Now
Search any question & find its solution
Question: Answered & Verified by Expert
The smallest possible natural number n, for which the equation x2-nx+2014=0 has integral roots, is
MathematicsQuadratic EquationJEE Main
Solution:
2665 Upvotes Verified Answer
The correct answer is: 91
In x2-nx+2014=0

α+β=n and αβ=2014

Now,

αβ=2014=1×2014 or -1×-2014

=2×1007 or -2×-1007

=19×106 or -19×-106

=38×53 or -38×-53

For least possible value, n=α+β

=38+53

=91

Looking for more such questions to practice?

Download the MARKS App - The ultimate prep app for IIT JEE & NEET with chapter-wise PYQs, revision notes, formula sheets, custom tests & much more.