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Question: Answered & Verified by Expert
The solubility of BaSO4 in water is 2.42×10-gL-1 at 298 K. The value of its solubility product (Ksp) will be (Given molar mass of BaSO4=233 gmol-1 )
ChemistryIonic EquilibriumNEET
Options:
  • A 1.08×10-14 mol2L-2
  • B 1.08×10-12 mol2L-2
  • C 1.08×10-10 mol2L-2
  • D 1.08×10-mol2L-2
Solution:
1851 Upvotes Verified Answer
The correct answer is: 1.08×10-10 mol2L-2
Solubility of BaSO 4 ,s= 2.42× 10 3 233 molL 1
=1.04×10-5(molL-1)
BaSO 4 s Ba 2+ s aq + SO 4 2 s sq
Ksp=[Ba2+][SO42-]=s2
=(1.04×10-5)2
=1.08×10-10mol2L-2

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