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Question: Answered & Verified by Expert
The solubility of Sr(OH)2at 298 K is 19.23 g/L of solution. Calculate the concentrations of strontium and hydroxyl ions and the pH of the solution.
ChemistryIonic EquilibriumNEET
Options:
  • A [Sr2+] = 0.15 M, [OH-] = 0.31 M, pH = 13.50
  • B [Sr2+] = 0.08 M, [OH-] = 0.16 M, pH = 12.00
  • C [Sr2+] = 0.16 M, [OH-] = 0.08 M, pH = 12.60
  • D [Sr2+] = 0.04 M, [OH-] = 0.02 M, pH = 13.80
Solution:
2880 Upvotes Verified Answer
The correct answer is: [Sr2+] = 0.15 M, [OH-] = 0.31 M, pH = 13.50
Correct Option is : (A)
[Sr2+] = 0.15 M, [OH-] = 0.31 M, pH = 13.50

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