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The solubility product of a sparingly soluble salt $\mathrm{AX}_2$ is $3.2 \times 10^{-8}$. What is it's solubility in $\mathrm{mol} \mathrm{dm}^{-3}$
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The correct answer is:
$2.0 \times 10^{-3}$
$\begin{aligned} & \mathrm{Ksp}=\left[\mathrm{A}^{2+}\right]\left[\mathrm{X}^{-}\right]^2 \\ & =\mathrm{S}(2 \mathrm{~S})^2 \\ & =4 \mathrm{~S}^3 \\ & 3.2 \times 10^{-8} 4 \mathrm{~S}^3 \\ & \mathrm{~S}^3=\frac{32}{4} \times 10^{-9}=8 \times 10^{-9} \\ & \mathrm{~S}=2 \times 10^{-3} \mathrm{~mol} . \mathrm{dm}^{-3} \text {. } \\ & \end{aligned}$
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