The solubility product of C r ( O H ) 3 at 298 K is 6.0 × 1 0 - 31 . The concentration of hydroxide ions in a saturated solution of C r ( O H ) 3 will be

Question

The solubility product of C r ( O H ) 3 at 298 K is 6.0 × 1 0 - 31 . The concentration of hydroxide ions in a saturated solution of C r ( O H ) 3 will be, ( 18 × 1 0 - 31 ) 1 / 4, ( 4.86 × 1 0 - 29 ) 1 / 4, ( 18 × 1 0 - 31 ) 1 / 2, ( 2.22 × 1 0 - 31 ) 1 / 4

MARKS App · Accepted Answer

Cr OH 3 ⇌ Cr 3 + s + 3 OH − 3 s 6 × 1 0 - 31 = S × ( 3 S ) 3 6 × 1 0 - 31 = 27 S 4 S = 6 27 × 1 0 - 31 1 / 4 [ O H - ] = 3 S = 3 6 27 × 1 0 - 31 1 / 4 = ( 18 × 1 0 - 31 ) 1 / 4 M

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