Join the Most Relevant JEE Main 2025 Test Series & get 99+ percentile! Join Now
Search any question & find its solution
Question: Answered & Verified by Expert
The solubility product values of barium sulphate and barium carbonate are 1.0 × 10–10 and 5.0 × 10–9 respectively When the two salts are simultaneously equilibrated in pure water the ratio of SO 4 2 CO 3 2 is
ChemistryIonic EquilibriumJEE Main
Options:
  • A 0.02
  • B 0.10
  • C 0.05
  • D 0.12
Solution:
2725 Upvotes Verified Answer
The correct answer is: 0.02
K sp 1 = Ba 2 + SO 4 2 -

K sp 2 = Ba 2 + CO 3 2 -

K sp 1 K sp 2 = SO 4 2 - CO 3 2 - = 1 × 1 0 - 1 0 5 × 1 0 - 9 = 0.02

Looking for more such questions to practice?

Download the MARKS App - The ultimate prep app for IIT JEE & NEET with chapter-wise PYQs, revision notes, formula sheets, custom tests & much more.