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Question: Answered & Verified by Expert
The solution of differential equation x2+1dydx+y2+1=0 is….
MathematicsDifferential EquationsMHT CETMHT CET 2019 (Shift 1)
Options:
  • A x+y=c
  • B x2+1y2+1=c
  • C x2=y2+c
  • D tan-1x+tan-1y=c
Solution:
2442 Upvotes Verified Answer
The correct answer is: tan-1x+tan-1y=c
We have, differential equation
x2+1dydx+y2+1=0
dxx2+1=-dyy2+1
On the integrating both sides, we get
dxx2+1=-dyy2+1
tan-1x=-tan-1y+C
tan-1x+tan-1y=C

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