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Question: Answered & Verified by Expert

The solution of the differential equation 3x2sin1x+ydx=xcos1xdx-xdy is

(where, c is an arbitrary constant)

MathematicsDifferential EquationsJEE Main
Options:
  • A sin1x=xy+c
  • B x3sin1x+xy=c
  • C x3sin1x=xy+c
  • D sinx=x3y+c
Solution:
2277 Upvotes Verified Answer
The correct answer is: x3sin1x+xy=c
Given equation can be written as dx3sin1x+dxy=0 
solution is x3sin1x+xy=c

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