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The solution of the differential equation $\frac{d y}{d x}=\sec x(\sec x+\tan x)$ is
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The correct answer is:
$y=\sec x+\tan x+c$
$\frac{d y}{d x}=\sec x(\sec x+\tan x) \Rightarrow \frac{d y}{d x}=\sec ^2 x+\sec x \tan x$
Now integrating both sides, we get $y=\tan x+\sec x+c$.
Now integrating both sides, we get $y=\tan x+\sec x+c$.
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