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Question: Answered & Verified by Expert
The solution of the differential equation dydx=y2+xlnx2xy is (where, c is the constant of integration)
MathematicsDifferential EquationsJEE Main
Options:
  • A 2x2=ylnx2+2cy
  • B 2y2=xlnx2+2cx
  • C x2=ylnx2+c
  • D 2y2=xylnx2+cx
     
Solution:
2790 Upvotes Verified Answer
The correct answer is: 2y2=xlnx2+2cx

2xydydx=y2+xlnx
2ydydx-y2x=lnx
Put, y2=t2ydydx=dtdx
dtdx-tx=lnx
I.F. =e-1xdx=e-lnx=1x

The solution is
tx=lnxxdx
tx=lnx22+c
y2x=lnx22+c
2y2=xlnx2+2cx

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