The solution of the differential equation d y d x = y c o s x - y 2 sin ⁡ x is equal to (where c is an arbitrary constant)

Question

The solution of the differential equation d y d x = y c o s x - y 2 sin ⁡ x is equal to (where c is an arbitrary constant), sin ⁡ x = x - y + c, sin ⁡ x = x + y + c, sin ⁡ x = x y + c y, sin ⁡ x x = y + c

MARKS App · Accepted Answer

d y d x = y c o s x - y 2 sin ⁡ x y cos ⁡ xdx - sin ⁡ x d y = y 2 d x y c o s x . d x - sin ⁡ x . d y y 2 = d x d sin ⁡ x y = d x On integrating, we get, sin ⁡ x y = x + c sin ⁡ x = x y + c y

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