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The solution of the equation $\left(1+x^2\right) \frac{d y}{d x}=1$ is
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The correct answer is:
$y=\tan ^{-1} x+c$
$\left(1+x^2\right) \frac{d y}{d x}=1 \Rightarrow \frac{d y}{d x}=\frac{1}{1+x^2}$
On integrating, $y=\tan ^{-1} x+c$
On integrating, $y=\tan ^{-1} x+c$
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