The specific heat of water $=4200\text{ J}$ ${\text{kg}}^{–1}{\text{ K}}^{–1}$ and the latent heat of ice $=3.4\times {10}^5\text{ J}$ k${\text{g}}^{–1}$. $100$ grams of ice at $0{}^{\text{o}}\text{C}$ is placed in $200\text{ g}$ of water at $25{}^{\text{o}}\text{C}$. The amount of ice that will melt as the temperature of water reaches $0{}^{\text{o}}\text{C}$ is close to (in grams)