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Question: Answered & Verified by Expert
The specific rotation of a pure enantiomer is +10° . The observed rotation, if it is isolated from a reaction with 30% racemisation and 70% inversion is
ChemistryGeneral Organic ChemistryJEE Main
Options:
  • A +10°
  • B -10°
  • C 3°
  • D -7°
Solution:
2503 Upvotes Verified Answer
The correct answer is: -7°
Specific rotation of inverted isomer =-10°

Angle of rotation =(Specific rotation of inverted isomer)×(Fraction of inversion)

=-10×70100=-7°

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