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Question: Answered & Verified by Expert
The stability of dihalides of $\mathrm{Si}, \mathrm{Ge}, \mathrm{Sn}$ and $\mathrm{Pb}$ follows the sequence.
ChemistryAlcohols Phenols and EthersTS EAMCETTS EAMCET 2018 (07 May Shift 1)
Options:
  • A $\mathrm{Si} X_2 < \operatorname{Ge} X_2 < \mathrm{PbX}_2 < \operatorname{Sn} X_2$
  • B $\mathrm{Si} X_2 < \operatorname{Ge} X_2 < \operatorname{Sn} X_2 < \mathrm{PbX}_2$
  • C $\mathrm{Pb} X_2 < \operatorname{Sn} X_2 < \operatorname{Ge} X_2 < \operatorname{Si} X_2$
  • D $\operatorname{GeX} X_2 < \operatorname{SiX} X_2 < \operatorname{Sn} X_2 < \mathrm{PbX}_2$
Solution:
1107 Upvotes Verified Answer
The correct answer is: $\mathrm{Si} X_2 < \operatorname{Ge} X_2 < \operatorname{Sn} X_2 < \mathrm{PbX}_2$
Due to inert pair effect, the stability of +2 oxidation state increases as we move down the group.

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