The standard enthalpy of neutralization of strong acid and strong base is - 57.3 k J equiv − 1 . If the enthalpy of neutralization of the first proton of aqueous H 2 S is - 33.7 k J m o l - 1 then the pK a 1 of H 2 S is

Question

The standard enthalpy of neutralization of strong acid and strong base is - 57.3 k J equiv − 1 . If the enthalpy of neutralization of the first proton of aqueous H 2 S is - 33.7 k J m o l - 1 then the pK a 1 of H 2 S is, 23.6 × 1 0 3 - T Δ S ° 2.303 R T, 2.303 R T 23.6 - T Δ S °, T Δ S ° - 23.6 R T, 2.303 T Δ S ° - 23.6 R T

MARKS App · Accepted Answer

H 2 S ⇌ H + + H S - Δ H i o n = 23.6 k J ∴ Δ G ° = 23.6 × 1 0 3 - T Δ S ° = - 2.303 R T l o g K a 1 ∴ P K a 1 = 23.6 × 1 0 3 - T Δ S ° 2.303 R T

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