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The statement pattern $(p \wedge q) \vee(\sim p \wedge q) \vee(r \wedge \sim q)$ is logical equivalent to
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The correct answer is:
$q \vee r$
$\begin{aligned} & (p \wedge q) \vee(\sim p \wedge q) \vee(r \wedge \sim q) \\ & \equiv\{(p \vee \sim p) \wedge q\} \vee(r \wedge \sim q) \\ & \equiv(t \wedge q) \vee(r \wedge \sim q) \\ & \equiv q \vee(r \wedge \sim q) \\ & \equiv(q \vee r) \wedge(q \vee \sim q) \\ & \equiv(q \vee r) \wedge t \\ & \equiv q \vee r\end{aligned}$
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