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The successive ionisation energies (starting from the $1^{\text {st }}$ ) of anelementare $801,2430,3660,25,000$ and $32,800 \mathrm{~kJ} \mathrm{~mol}^{-1}$, respectively. The element is
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The correct answer is:
$\mathrm{B}$
There are five successive ionization energies means 5 electrons are successively removed. Therefore, the atomic no. of the element is 5 .
$\therefore \quad$ The element is ' $\mathrm{B}$ '.
$\therefore \quad$ The element is ' $\mathrm{B}$ '.
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