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The sum of all 4-digit numbers that can be formed using the digits 2, 3, 4, 5, 6 without repetition, is
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The correct answer is:
533280
Given digits are 2, 3, 4, 5, 6
Sum of all 4-digit numbers formed by the using 2, 3, 4, 5, 6 without repetition
$\begin{aligned}
& =41(2+3+4+5+6)\left(10^3+10^2+10^1+10^0\right) \\
& =24(20)(1000+100+10+1) \\
& =(480)(1111)=533280
\end{aligned}$
Sum of all 4-digit numbers formed by the using 2, 3, 4, 5, 6 without repetition
$\begin{aligned}
& =41(2+3+4+5+6)\left(10^3+10^2+10^1+10^0\right) \\
& =24(20)(1000+100+10+1) \\
& =(480)(1111)=533280
\end{aligned}$
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