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Question: Answered & Verified by Expert
The sum of the following series 1+6+912+22+327+1212+22+32+429+15(12+22++52)11+.... up to 15 terms, is:
MathematicsSequences and SeriesJEE MainJEE Main 2019 (09 Jan Shift 2)
Options:
  • A 7520
  • B 7510
  • C 7830
  • D 7820
Solution:
2626 Upvotes Verified Answer
The correct answer is: 7820

tn=3n12+22+32++n22n+1=3n×nn+12n+16 2n+1

=12 n3+n2

S15=n=115tn=n=11512n3+n2

=12n=115n3+n=115n2


=12×15×1622+15×16×316    n3=nn+122, n2=nn+1n+26

=7200+620

=7820

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