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Question: Answered & Verified by Expert
The sum of the intercepts on the coordinate axes made by a line passing through the point a,b and the common point of xa+yb=1 and xb+ya=1 is
MathematicsStraight LinesJEE Main
Options:
  • A a-b2a+bab
  • B b-aa2-b2ab
  • C a+ba2-b2ab
  • D a-ba2+b2ab
Solution:
2302 Upvotes Verified Answer
The correct answer is: b-aa2-b2ab
Point of intersection of xa+yb=1 and xb+ya=1 is aba+b,aba+b
Now, line joining a,b and aba+b,aba+b is y-bx-a=aba+b-baba+b-a
y-ba2=b2x-axab-ab+yba-ba=1
sum of the x intercept and the y intercept is equal to ab-ab+ba-ba=b-aa2-b2ab

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