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The sum of the series :
$(2)^2+2(4)^2+3(6)^2+\ldots$ upto 10 terms is :
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$(2)^2+2(4)^2+3(6)^2+\ldots$ upto 10 terms is :
Solution:
1413 Upvotes
Verified Answer
The correct answer is:
12100
12100
$2^2+2(4)^2+3(6)^2+\ldots \ldots$ upto 10 terms $=2^2\left[1^3+2^3+3^3+\ldots \ldots\right.$ upto 10 terms $]$
$=4 \cdot\left(\frac{10 \times 11}{2}\right)^2=12100$
$=4 \cdot\left(\frac{10 \times 11}{2}\right)^2=12100$
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