Search any question & find its solution
Question:
Answered & Verified by Expert
The surface tension of soap solution is $0.03 \mathrm{~N} / \mathrm{m}$. The work done in blowing to form a soap bubble of surface area $40 \mathrm{~cm}^2$, (in J), is
Options:
Solution:
1548 Upvotes
Verified Answer
The correct answer is:
$2.4 \times 10^{-4}$
In case of soap bubble
$$
\begin{aligned}
W & =T \times 2 \times \Delta A \\
& =0.03 \times 2 \times 40 \times 10^{-4} \\
& =2.4 \times 10^{-4} \mathrm{~J}
\end{aligned}
$$
$$
\begin{aligned}
W & =T \times 2 \times \Delta A \\
& =0.03 \times 2 \times 40 \times 10^{-4} \\
& =2.4 \times 10^{-4} \mathrm{~J}
\end{aligned}
$$
Looking for more such questions to practice?
Download the MARKS App - The ultimate prep app for IIT JEE & NEET with chapter-wise PYQs, revision notes, formula sheets, custom tests & much more.