Join the Most Relevant JEE Main 2025 Test Series & get 99+ percentile! Join Now
Search any question & find its solution
Question: Answered & Verified by Expert

The system is released form rest with both the springs in unstretched position. Mass of each block is 1 kg and force constant of each spring is 10 N/m. Assume pulleys and strings are massless and all contacts are smooth.Then which of the following is incorrect. (g = 10 m/s2)

PhysicsWork Power EnergyJEE Main
Options:
  • A Extension of horizontal spring in equilibrium is 2/5 m
  • B Extension of vertical spring in equilibrium is 1/5 m
  • C Maximum speed of the block A is 8 5 m/s
  • D Maximum speed of the block A is 1 4 m/s
Solution:
2132 Upvotes Verified Answer
The correct answer is: Maximum speed of the block A is 1 4 m/s
The system is released...


         
                  

  T = 2 kx 5 kx = mg

x = mg 5 k = 1 × 1 0 5 × 1 0 = 1 5

(ii)  1 g x = 1 2 1 v 2 + 1 2 1 2 v 2 x + 1 2 1 0 0.2 2 + 1 2 1 0 0.4 2

2 = V 2 2 1 + 4 + 1 2 0.4 + 1.6 v = 2 5

v A = 2 v = 2 5 2 = 8 5

So only wrong option is (iv)

Looking for more such questions to practice?

Download the MARKS App - The ultimate prep app for IIT JEE & NEET with chapter-wise PYQs, revision notes, formula sheets, custom tests & much more.