The system shown in the figure is in equilibrium and at rest. The spring and string are massless, now the string is cut. The acceleration of mass 2 m and m just after the string is cut will be

Question

The system shown in the figure is in equilibrium and at rest. The spring and string are massless, now the string is cut. The acceleration of mass 2 m and m just after the string is cut will be, g 2 upward, g downward, g upward, downward, g upward, 2 g downward, 2 g upward, g downward

MARKS App · Accepted Answer

Initially under equilibrium of mass m T = m g Now, the string is cut. Therefore, T = m g force is decreased on mass m upward and downwards on mass 2 m . ∴ a m = m g m = g d o w n w a r d s and a 2 m = m g 2 m = g 2 ( u p w a r d s )

Search any question & find its solution

Looking for more such questions to practice?