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Question: Answered & Verified by Expert
The tangent to the curve, y=xex2 passing through the point 1,e also passes through the point:
MathematicsApplication of DerivativesJEE MainJEE Main 2019 (10 Jan Shift 2)
Options:
  • A 43, 2e
  • B 2, 3e
  • C 53, 2e
  • D 3, 6e
Solution:
2103 Upvotes Verified Answer
The correct answer is: 43, 2e
Given y=xex2

dydx=2x2ex2+ex2

dydx at 1, e=3e

Equation of tangent is y-e=3ex-1, which passes through 43,2e

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