Search any question & find its solution
Question:
Answered & Verified by Expert
The tangent to the curve \( y=x^{3}+1 \) at \( (1,2) \) makes an angle \( \theta \) with y axis, then the value of \( \tan \theta \) is
Options:
Solution:
2186 Upvotes
Verified Answer
The correct answer is:
\( -\frac{1}{3} \)
Given equation of curve

Here
\[
\theta=90^{\circ}+\phi . \text { Then }, \tan \theta=\tan \left(90^{\circ}+\phi\right)=-\cot \phi
\]
Now,
\[
\tan \theta=\frac{d y}{d x}=\frac{d}{d x}\left(x^{3}+1\right)=3 x^{2}
\]
At point \( (1,2) \), we have \( \left.\frac{d y}{d x}\right|_{(1,2)}=\left.3 x^{2}\right|_{(1,2)}=3 \)
Therefore, required value of \( \theta \) is
\[
-\cot \phi=-\frac{1}{3}
\]
In the above diagram, \( \theta \) is to be considered as the angle made by tangent with y-axis and not \( \theta^{\prime} \) [for e.g., when we say

Here
\[
\theta=90^{\circ}+\phi . \text { Then }, \tan \theta=\tan \left(90^{\circ}+\phi\right)=-\cot \phi
\]
Now,
\[
\tan \theta=\frac{d y}{d x}=\frac{d}{d x}\left(x^{3}+1\right)=3 x^{2}
\]
At point \( (1,2) \), we have \( \left.\frac{d y}{d x}\right|_{(1,2)}=\left.3 x^{2}\right|_{(1,2)}=3 \)
Therefore, required value of \( \theta \) is
\[
-\cot \phi=-\frac{1}{3}
\]
In the above diagram, \( \theta \) is to be considered as the angle made by tangent with y-axis and not \( \theta^{\prime} \) [for e.g., when we say
Looking for more such questions to practice?
Download the MARKS App - The ultimate prep app for IIT JEE & NEET with chapter-wise PYQs, revision notes, formula sheets, custom tests & much more.