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The temperature coefficient of a reaction is \( 2 \). When the temperature is increased from \( 30^{\circ} \mathrm{C} \) to
\( 90^{\circ} \mathrm{C} \), the rate of reaction is increased by
Options:
\( 90^{\circ} \mathrm{C} \), the rate of reaction is increased by
Solution:
1229 Upvotes
Verified Answer
The correct answer is:
\( 64 \) times
Using the formula, \( \frac{K_{T_{2}}}{K_{T_{1}}}=\mu^{\Delta T / 10} \)
\[
=2^{\frac{90-30}{10}}
\]
\[
=2^{6}=64 \text { times. }
\]
\[
=2^{\frac{90-30}{10}}
\]
\[
=2^{6}=64 \text { times. }
\]
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