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Question: Answered & Verified by Expert
The temperature of an ideal gas is increased from $27^{\circ} \mathrm{C}$ to $127^{\circ} \mathrm{C}$, then percentage increase in $\mathrm{v}_{\mathrm{rms}}$

is
PhysicsKinetic Theory of GasesBITSATBITSAT 2013
Options:
  • A $37 \%$
  • B $11 \%$
  • C $33 \%$
  • D $15.5 \%$
Solution:
1813 Upvotes Verified Answer
The correct answer is: $15.5 \%$
We know, $\mathrm{V}_{\mathrm{mms}}=\sqrt{\frac{3 \mathrm{RT}}{\mathrm{M}}}$

$\Rightarrow \%$ increase in

$$

\begin{array}{l}

\mathrm{V}_{\mathrm{rms}}=\frac{\sqrt{\frac{3 \mathrm{R} \mathrm{T}_{2}}{\mathrm{M}}}-\sqrt{\frac{3 \mathrm{RT}_{1}}{\mathrm{M}}}}{\sqrt{\frac{3 \mathrm{RT}_{1}}{\mathrm{M}}}} \times 100 \\

=\frac{\sqrt{\mathrm{T}_{2}}-\sqrt{\mathrm{T}_{1}}}{\sqrt{\mathrm{T}_{1}}} \times 100 \\

=\frac{\sqrt{400}-\sqrt{300}}{\sqrt{300}} \times 100 \\

=\frac{20-17.32}{17.32} \times 100=15.5 \%

\end{array}

$$

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