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The temperature of $K$ at which $\Delta G=0$, for a given reaction with $\Delta H=-20.5 \mathrm{~kJ} \mathrm{~mol}^{-1}$ and $\Delta S=-50.0 \mathrm{JK}^{-1} \mathrm{~mol}^{-1}$ is
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Verified Answer
The correct answer is:
$410$
From Gibbs-Helmholtz reaction,
$$
\begin{aligned}
\Delta G & =\Delta H-T \Delta S \\
0 & =-20.5 \times 10^3-T \times(-50.0) \\
\therefore T & =\frac{-20.5 \times 10^3}{-50.0}=410 \mathrm{~K}
\end{aligned}
$$
$$
\begin{aligned}
\Delta G & =\Delta H-T \Delta S \\
0 & =-20.5 \times 10^3-T \times(-50.0) \\
\therefore T & =\frac{-20.5 \times 10^3}{-50.0}=410 \mathrm{~K}
\end{aligned}
$$
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