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Question: Answered & Verified by Expert
The temperature of the cold junction of thermocouple is $0^{\circ} \mathrm{C}$ and the temperature of hot junction is $T^{\circ} \mathrm{C}$. The emf is $E=16 T-0.04 T^2 \quad \mu \mathrm{V}$. The inversion temperature $T_i$ is
PhysicsThermal Properties of MatterJIPMERJIPMER 2015
Options:
  • A $300^{\circ} \mathrm{C}$
  • B $200^{\circ} \mathrm{C}$
  • C $500^{\circ} \mathrm{C}$
  • D $400^{\circ} \mathrm{C}$
Solution:
1491 Upvotes Verified Answer
The correct answer is: $400^{\circ} \mathrm{C}$
As,
$E=16 T-0.04 T^2$
At inversion temperature, $E=0$
$\begin{aligned} \Rightarrow \quad 16 T-0.04 T^2 & =0 \\ \Rightarrow \quad T_i & =\frac{16}{0.04}=400^{\circ} \mathrm{C}\end{aligned}$

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