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Question: Answered & Verified by Expert
The term independent of \( x \) in the expansion of \( \left(\frac{x+1}{x^{2 / 3}-x^{1 / 3}+1}-\frac{x-1}{x-x^{1 / 2}}\right)^{10} \), where \( x \neq 0,1 \) is equal to
MathematicsBinomial TheoremJEE Main
Solution:
2080 Upvotes Verified Answer
The correct answer is: 210

x+1x2/3-x1/3+1-x-1x-x1/210

=x1/3+1-x1/2+1x1/210

=x1/3-1x1/210

Now the r+1th Term

Tr+1=Cr10x1/310-r·-1x1/2r

For independent term

10-r3-r2=0r=4

T5=C410=210

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