Join the Most Relevant JEE Main 2025 Test Series & get 99+ percentile! Join Now
Search any question & find its solution
Question: Answered & Verified by Expert
The term independent of x in the expansion of x+1x2/3-x1/3+1-x-1x-x1/210, x1, is equal to ___.
MathematicsBinomial TheoremJEE MainJEE Main 2021 (18 Mar Shift 2)
Solution:
2583 Upvotes Verified Answer
The correct answer is: 210

Given x+1x2/3-x1/3+1-x-1x-x1/210

x1/3+1-x+1x10

x1/3-x-1/210

General term is Tr+1=10Crx1/310-r-x-1/2r

 10-r3-r2=020-2r-3r=0

r=4

Then, T5=C410=10×9×8×74×3×2×1=210

Looking for more such questions to practice?

Download the MARKS App - The ultimate prep app for IIT JEE & NEET with chapter-wise PYQs, revision notes, formula sheets, custom tests & much more.