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The third term of a geometric progression is 4 . The product of the first five terms is :
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The correct answer is:
$4^4$
$4^4$
Here, $t_3=4 \Rightarrow a r^2=4$
$\therefore$ Product of first five terms $=a$. $a r \cdot a r^2 \cdot a r^3 \cdot a r^4$ $=a^5 r^{10}=\left(a r^2\right)^5=(4)^5$
$\therefore$ Product of first five terms $=a$. $a r \cdot a r^2 \cdot a r^3 \cdot a r^4$ $=a^5 r^{10}=\left(a r^2\right)^5=(4)^5$
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