Join the Most Relevant JEE Main 2025 Test Series & get 99+ percentile! Join Now
Search any question & find its solution
Question: Answered & Verified by Expert
The time in which a force of $2 \mathrm{~N}$ produces a change of momentum of $0.4 \mathrm{~kg}-\mathrm{ms}^{-1}$ in the body is
PhysicsLaws of MotionJEE Main
Options:
  • A $0.2 \mathrm{~s}$
  • B $0.02 \mathrm{~s}$
  • C $0.5 \mathrm{~s}$
  • D $0.05 \mathrm{~s}$
Solution:
1370 Upvotes Verified Answer
The correct answer is: $0.2 \mathrm{~s}$
$\vec{F}=\frac{\Delta \vec{p}}{\Delta t} \Rightarrow \Delta t=\frac{|\Delta \vec{p}|}{|\vec{F}|}=\frac{0.4}{2}=0.2 \mathrm{~s}$

Looking for more such questions to practice?

Download the MARKS App - The ultimate prep app for IIT JEE & NEET with chapter-wise PYQs, revision notes, formula sheets, custom tests & much more.