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The time taken for $10 \%$ completion of a first order reactin is 20 mins. Then, for $19 \%$ completion, the reaction will take
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Verified Answer
The correct answer is:
$40 \mathrm{mins}$
$t=\frac{2.303}{\lambda} \log \frac{\mathrm{N}_0}{\mathrm{~N}}$
$\begin{aligned} & 20=\frac{2.303}{\lambda} \log \frac{100}{90} \\ & t=\frac{2.303}{\lambda} \log \frac{100}{81}\end{aligned}$
equation (i) / (ii)
$\therefore t=40 \mathrm{~min}$.
$\begin{aligned} & 20=\frac{2.303}{\lambda} \log \frac{100}{90} \\ & t=\frac{2.303}{\lambda} \log \frac{100}{81}\end{aligned}$
equation (i) / (ii)
$\therefore t=40 \mathrm{~min}$.
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