Join the Most Relevant JEE Main 2025 Test Series & get 99+ percentile! Join Now
Search any question & find its solution
Question: Answered & Verified by Expert
The total molarity and normality of all the ions present in a solution containing 0.1 M of CuSO4 and 0.1 M of Al2(SO4)3 is
ChemistrySome Basic Concepts of ChemistryNEET
Options:
  • A 0.2 M, 0.2 N
  • B 0.7 M, 1.6 N
  • C 0.8 M, 1.6 N
  • D 1.6 M, 1.6 N
Solution:
2410 Upvotes Verified Answer
The correct answer is: 0.7 M, 1.6 N
mole of Cu2+=0.1 , mole of SO42-=0.1
mole of Al3+=0.2 , mole of SO42-=0.3
So total mole = 0.1 + 0.1 + 0.2 + 0.3 = 0.7
Also, eq. of Cu2+=0.2 , eq. of SO42-=0.2
Eq. of Al3+=0.6, Eq. of SO42-=0.6
So total eq. =0.2+0.2+0.6+0.6=1.6 .

Looking for more such questions to practice?

Download the MARKS App - The ultimate prep app for IIT JEE & NEET with chapter-wise PYQs, revision notes, formula sheets, custom tests & much more.