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The total number of moles of neutrons present in 108 mL H 2 O l are
ChemistrySome Basic Concepts of ChemistryJEE Main
Solution:
2195 Upvotes Verified Answer
The correct answer is: 48
density of H 2 O( l )= g/mL
mL contains =g H 2 O
108  mL contains =108 g H 2 O
Number of moles of H 2 O l = 1 0 8 1 8 = 6    
H has no neutron, Number of neutrons in O = 1 6 - 8 = 8
Number of moles of neutrons in 1 mole of H 2 O=0+8=8
Number of moles of neutrons in 6 mole of  H 2 O = 6 × 8 = 4 8

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