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The total number of possible enantiomeric pairs that can be obtained during mono-chlorination of 2-methylbutane is
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The correct answer is:
2
Its monochloro derivatives are as follows :
(i)
It will exist as enantiomeric pair (d and l-forms)
(ii)
no asymmetric C atom
(iii)
It will exist as enantiomeric pair (d- and l-forms)
(iv)
No asymmetric carbon atom
Hence, only two enantiomeric pairs will be obtained by the monochlorination of 2-methylbutane.
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