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The total number of possible isomers for squareplanar $\left[\mathrm{Pt}(\mathrm{Cl})\left(\mathrm{NO}_2\right)\left(\mathrm{NO}_3\right)(\mathrm{SCN})\right]^{2-}$ is:
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12
12
The square planar complex of the type $[\mathrm{Mabcd}]^{\mathrm{n} \pm}$, where all four ligands are different, has 3 geometrical isomers. But if one of the ligands is ambidentate, then $2 \times$ $3=6$ geometrical isomers are possible. But if two ligands are ambidentate, then $4 \times 3=$ 12 geometrical isomers are possible.
In the given example, $\mathrm{NO}_2^{-}$and $\mathrm{SCN}^{-}$are ambidentate ligands.
In the given example, $\mathrm{NO}_2^{-}$and $\mathrm{SCN}^{-}$are ambidentate ligands.
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