Search any question & find its solution
Question:
Answered & Verified by Expert
The truth-table given below is for which gate
$\begin{array}{l|l|l|l|l}
A & 0 & 0 & 1 & 1 \\
\hline B & 0 & 1 & 0 & 1 \\
\hline C & 1 & 1 & 1 & 0
\end{array}$
Options:
$\begin{array}{l|l|l|l|l}
A & 0 & 0 & 1 & 1 \\
\hline B & 0 & 1 & 0 & 1 \\
\hline C & 1 & 1 & 1 & 0
\end{array}$
Solution:
2399 Upvotes
Verified Answer
The correct answer is:
NAND
For 'NAND' gate $C=\overline{A \cdot B}$ i.e. $\overline{0.0}=\overline{0}=1, \overline{0.1}=\overline{0}=1$ $\overline{1.0}=\overline{0}=1, \overline{1.1}=\overline{1}=0$
Looking for more such questions to practice?
Download the MARKS App - The ultimate prep app for IIT JEE & NEET with chapter-wise PYQs, revision notes, formula sheets, custom tests & much more.