Search any question & find its solution
Question:
Answered & Verified by Expert
The two lines $x=a y+b, z=c y+d$ and $x=a^{\prime} y+b^{\prime} z=c^{\prime} y+d^{\prime}$ will be perpendicular, if and only if
Options:
Solution:
2929 Upvotes
Verified Answer
The correct answer is:
$a a^{\prime}+c c^{\prime}+1=0$
$a a^{\prime}+c c^{\prime}+1=0$
$\frac{\mathrm{x}-\mathrm{b}}{\mathrm{a}}=\frac{\mathrm{y}}{1}=\frac{3-\mathrm{d}}{\mathrm{c}} ; \frac{\mathrm{x}-\mathrm{b}^{\prime}}{\mathrm{a}^{\prime}}=\frac{\mathrm{y}}{1}=\frac{3-\mathrm{d}^{\prime}}{\mathrm{c}^{\prime}}$
For perpendicular $\mathrm{aa}^{\prime}+1+\mathrm{cc}^{\prime}=0$
For perpendicular $\mathrm{aa}^{\prime}+1+\mathrm{cc}^{\prime}=0$
Looking for more such questions to practice?
Download the MARKS App - The ultimate prep app for IIT JEE & NEET with chapter-wise PYQs, revision notes, formula sheets, custom tests & much more.