Search any question & find its solution
Question:
Answered & Verified by Expert
The two vectors $\overrightarrow{\mathrm{A}}$ and $\overrightarrow{\mathrm{B}}$ are drawn from a common point and $\overrightarrow{\mathrm{C}}=\overrightarrow{\mathrm{A}}+\overrightarrow{\mathrm{B}},$ then angle
between $\overrightarrow{\mathrm{A}}$ and $\overrightarrow{\mathrm{B}}$ is -
(1) $90^{\circ}$ if $\mathrm{C}^{2}=\mathrm{A}^{2}+\mathrm{B}^{2}$
(2) greater than $90^{\circ}$ if $\mathrm{C}^{2}<\mathrm{A}^{2}+\mathrm{B}^{2}$
(3) greater than $90^{\circ}$ if $\mathrm{C}^{2}>\mathrm{A}^{2}+\mathrm{B}^{2}$
(4) less than $90^{\circ}$ if $\mathrm{C}^{2}>\mathrm{A}^{2}+\mathrm{B}^{2}$
Correct options are -
Options:
between $\overrightarrow{\mathrm{A}}$ and $\overrightarrow{\mathrm{B}}$ is -
(1) $90^{\circ}$ if $\mathrm{C}^{2}=\mathrm{A}^{2}+\mathrm{B}^{2}$
(2) greater than $90^{\circ}$ if $\mathrm{C}^{2}<\mathrm{A}^{2}+\mathrm{B}^{2}$
(3) greater than $90^{\circ}$ if $\mathrm{C}^{2}>\mathrm{A}^{2}+\mathrm{B}^{2}$
(4) less than $90^{\circ}$ if $\mathrm{C}^{2}>\mathrm{A}^{2}+\mathrm{B}^{2}$
Correct options are -
Solution:
1785 Upvotes
Verified Answer
The correct answer is:
1,2,4
No Solution available
Looking for more such questions to practice?
Download the MARKS App - The ultimate prep app for IIT JEE & NEET with chapter-wise PYQs, revision notes, formula sheets, custom tests & much more.