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The type of hybridisation of boron in diborane is
(a) \(s p\)
(b) \(s p^2\)
(c) \(s p^3\)
(d) \(d s p^2\)
(a) \(s p\)
(b) \(s p^2\)
(c) \(s p^3\)
(d) \(d s p^2\)
Solution:
1655 Upvotes
Verified Answer
In \(\mathrm{B}_2 \mathrm{H}_6\), B is \(\mathrm{sp}^3\)-hybridized. Therefore, option (c) is correct.
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