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The unit of electric field is not equivalent to
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The correct answer is:
$J / C$
By unit and dimension - electric feild.
$\frac{N}{C}=\frac{\text { volt }}{\text { meter }}=\frac{\mathrm{J}}{\mathrm{c}-\mathrm{mt}}$
Therefore, dimensions of $\mathrm{E}=\mathrm{MLT}^{-3} \mathrm{~A}^{-1}$ which is a vector quantity. So, the correct answer is 2 : J/C
Because, it gives the answer work done per unit charge which is called Potential.
$\frac{N}{C}=\frac{\text { volt }}{\text { meter }}=\frac{\mathrm{J}}{\mathrm{c}-\mathrm{mt}}$
Therefore, dimensions of $\mathrm{E}=\mathrm{MLT}^{-3} \mathrm{~A}^{-1}$ which is a vector quantity. So, the correct answer is 2 : J/C
Because, it gives the answer work done per unit charge which is called Potential.
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