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Question: Answered & Verified by Expert
The value of 02x2-2x+4sinx-12x2-4x+5dx is equal to
MathematicsDefinite IntegrationJEE Main
Solution:
1545 Upvotes Verified Answer
The correct answer is: 0
Let, Ι=02x2-2x+4sinx-1dx2x2-2x+5
02x-12+3sinx-12x-12+3dx
Put x-1=tdx=dt
I=-11t2+32t2+3sintdt=0
Since, this is an odd function

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