Search any question & find its solution
Question:
Answered & Verified by Expert
The value of alternating emf $E$ in the given circuit will be
Options:
Solution:
1083 Upvotes
Verified Answer
The correct answer is:
$100 \mathrm{~V}$
The given circuit diagram is $L-C-R$. series circuit, where
$$
\begin{aligned}
&V_{R}=80 \mathrm{~V}, V_{C}=100 \mathrm{~V} \\
&V_{L}=40 \mathrm{~V}
\end{aligned}
$$
Since, $\quad V_{C}>V_{L}$
Value of $\operatorname{emf} E$ is given as
$$
\begin{aligned}
E &=\sqrt{V_{R}^{2}+\left(V_{C}-V_{L}\right)^{2}} \\
&=\sqrt{80^{2}+(100-40)^{2}} \\
&=\sqrt{6400+3600}=100 \mathrm{~V}
\end{aligned}
$$
$$
\begin{aligned}
&V_{R}=80 \mathrm{~V}, V_{C}=100 \mathrm{~V} \\
&V_{L}=40 \mathrm{~V}
\end{aligned}
$$
Since, $\quad V_{C}>V_{L}$
Value of $\operatorname{emf} E$ is given as
$$
\begin{aligned}
E &=\sqrt{V_{R}^{2}+\left(V_{C}-V_{L}\right)^{2}} \\
&=\sqrt{80^{2}+(100-40)^{2}} \\
&=\sqrt{6400+3600}=100 \mathrm{~V}
\end{aligned}
$$
Looking for more such questions to practice?
Download the MARKS App - The ultimate prep app for IIT JEE & NEET with chapter-wise PYQs, revision notes, formula sheets, custom tests & much more.