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The value of $\cos ^{-1}\left(\cos \left(\frac{7 \pi}{6}\right)\right)$ is
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$\frac{5 \pi}{6}$
Let $\alpha$ and $\beta$ are roots of quadratic equation Given, $\frac{\alpha+\beta}{2}=34$ $\alpha+\beta=68$
and $\sqrt{\alpha \beta}=16$ $\alpha \beta=256$
$\therefore$ Required quadratic equation is, $x^{2}-(\alpha+\beta) x+\alpha \beta=0$ $x^{2}-68 x+256=0$
and $\sqrt{\alpha \beta}=16$ $\alpha \beta=256$
$\therefore$ Required quadratic equation is, $x^{2}-(\alpha+\beta) x+\alpha \beta=0$ $x^{2}-68 x+256=0$
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